WebIn triangle ABC,∠BAC=90 ∘, and AD is its bisector. If DE is drawn ⊥AC, prove that DE×(AB+AC)=AB×AC. Medium Solution Verified by Toppr It is given that AD is the bisector of ∠A of ΔABC. ∴ACAB= DCBD ⇒ ACAB+1= DCBD+1[Adding1onbothsides] ⇒ ACAB+AC= DCBD+DC ⇒ ACAB+AC= DCBC......(i) In ΔsCDEandCBA, we have … Web28 jun. 2024 · In the figure, if ∠BAC = 90° and AD ⊥ BC. Then, (A) BD . CD = BC 2 (B) AB . AC = BC 2 (C) BD . CD = AD 2 (D) AB . AC = AD 2 Solution: (C) In ∆ABC, ∠B + ∠BAC + ∠C = 180° ⇒ ∠B + 90° + ∠C = 180° ⇒ ∠B = 90° – ∠C Similarly, In ∆ADC, ∠D AC = 90° – ∠C In ∆ADB and ∆ADC, ∠D = ∠D = 90° ∠DBA = ∠D AC [each equal to (90° – ∠C) ∴ ∆ADB ~ …
In the figure, ABC is a right angled triangle and BAC=90∘. If AD⊥BC …
Web31 mrt. 2024 · Solution For In the figure, ABC is a right angled triangle and BAC=90∘. If AD⊥BC and BD=DC then prove that BC2=4AD2. [9×3=27 Solution For In the figure, ... ABC is a right angled triangle and BAC=90∘. If AD⊥BC and BD=DC then prove that BC2=4AD2. [9×3=27 The world’s only live instant tutoring platform. Become a ... WebSolution: Given, ABC is a triangle Also, ∠BAC = 90°, AD ⊥ BC and ∠BAD = 50° We have to find the measure of ∠ACD. By angle sum property of a triangle, We know that the sum of all the three interior angles of the triangle is equal to 180 degrees. Considering triangle ABD, ∠ADB + ∠ABD + ∠BAD = 180° 90° + ∠ABD + 50° = 180° ∠ABD + 140° = 180° ترجمه صفحه 78 عربی هشتم
[Solved] In Δ ABC, ∠A = 90°, AD ⊥ BC at D. If - Testbook
Web26 aug. 2024 · Best answer (c) BD.CD=AD² Explanation: From ∆ADB and ∆ADC, … WebQ. ABC is a triangle in which ∠ A = 90°, AN ⊥ BC, BC = 12 cm and AC = 5 cm. Find the … WebIn the figure, ABC is a right angled triangle and BAC = 90°. If AD BC and BD=DC then prove that BC² = 4AD2. KSEAB mathematics model question paper -23 Show more Show more Prove that "the... django matomo